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A box contains sweets of 6 different flavours. There are atleast 2 sweets of each flavour. A girl selects 3 sweets from the box. Given that these 3 sweets are not all of the same flavour, calculate the number of different ways she can select her 3 sweets.

Verified Answer :

nathan127

The question is totally irrelevent in context with the question. It's missing the "if she wants to only get different flavours".

For example, the answer could be:
1. Use her feet
2. Blind folded
3. Chained up behind her back

There are 50 different ways she can select her 3 sweets.

What is the combination?

The solution is obtained through a combination where we choose "r of n", where r is the amount of things we choose and n the total number of things that can be chosen.

A box contains sweets of 6 different flavours.

There are atleast 2 sweets of each flavour.

A girl selects 3 sweets from the box. Given that these 3 sweets are not all of the same flavour, calculate the number of different ways she can select her 3 sweets.

The three chosen sweets are not all of the same flavour, either she has chosen 3 different flavours, or she has chosen 2 different flavours.

If 3 different, then she is choosing 3 from 6, and we have 6C3 = 20.

If there are two different flavours, then there is one of one flavour and two of a different flavour.

The one has 6 choices of flavours and once chosen the two have five choices, making 6x5=30 possibilities.

Hence 50 ways in total.

Hence, there are 50 different ways she can select her 3 sweets.

Learn more about permutation combination here;

brainly.com/question/3929817

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