How do you solve 3/4n -18 = 1/4n -4
\(\frac{3}{4n}-18^{(4n}=\frac{1}{4n}-4^{(4n}\\\\ 3-72n=1-16n\\\\ -72n+16n=1-3\\\\ -56n=-2 \\\\ \boxed{n=\frac{-2}{-56}=\frac{1}{28}}\)
1) Multiply both sides by 4: 3n - 72 = n - 162) Subtract n from both sides: 2n - 72 = -163) Add 72 to both sides: 2n = 56n = 28.