setting d = 0 gives the points where she is at the surface.
therefore 0= 0.1t^2 - 3.5t + 6
apply the quadratic formula to get t = (3.5+- √12.25-40.16)/0.2
t = (3.5 3.1384709653)/0.2
t= 1.80764517352 and 33.1923548265
subtract the 2 to get the time difference between entry and exit you get
Δt = 31.384709653 seconds
That's as long as I haven't made a mistake :D