Answer:
The smallest zero is x = -3
Step-by-step explanation:
We have been given the equation \(h(x)=4x^2-8x-60\)
In order to find the zero, h(x) = 0
\(4x^2-8x-60=0\)
We can rewrite the equation by factor out 4
\(x^2-2x-15=0\)
Middle term can be written as -2x = -5x+3x
\(x^2-5x+3x-15=0\)
Now, we factored out GCF
\(x(x-5)+3(x-5)=0\)
Factored out the common term
\((x-5)(x+3)=0\)
Apply the zero product property
\((x-5)=0, (x+3)=0\\\\x=5,-3\)
Hence, the smallest zero is x = -3
