Verified Answer :

apologiabiology

remember
a^2-b^2=(a-b)(a+b)

16=4^2
x^4=(x^2)^2

so
16x^4-1=(4x^2)^2-(1)^2=(4x^2-1)(4x^2+1)
and the 4x^2-1 can be further factored
(2x)^2-(1)^2=(2x-1)(2x+1)

factoref rom is
(4x^2+1)(2x+1)(2x-1)
D is answer

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