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lala91101
lala91101 lala91101
  • 23-04-2016
  • Mathematics
Answered

how do i solve 4m^2+3m-1=0 using the quadratic formula

Verified Answer :

apologiabiology
apologiabiology apologiabiology
  • 23-04-2016

quadratic formulat is used when
a^2+bx+c=0
x= \(\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}\)
4m^2+3m-1=0
a=4
b=3
c=-1
input

x= \(\frac{-3+/- \sqrt{3^{2}-4(4)(-1)} }{2(4)}\)
x= \(\frac{-3+/- \sqrt{9+16} }{8}\)
x= \(\frac{-3+/- \sqrt{25} }{8}\)
x= \(\frac{-3+/-5 }{8}\)
x= \(\frac{-8}{8}\) or \(\frac{2}{8}\)

x=-1 or 1/4

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