To solve for 'x' we first collect simmilar terms. In this case I'll collect 'x'-terms on the left and non-'x'-terms on the right.
Start by subtracting 1/10 from both sides: \(3x+\frac{1}{10}-\frac{1}{10}=x-\frac{1}{7}-\frac{1}{10}\) and simplify: \(3x=x-\frac{10}{70}-\frac{7}{70}\) \(3x=x-\frac{17}{70}\)
We now have all non-'x'-terms on the right. We can get all the 'x' terms on the left by subtracting 'x' from both sides:
\(3x-x=x-\frac{17}{70}-x\) and simplifying: \(2x=-\frac{17}{70}\)
Then we can solve for x by dividing both sides by 2: \(\frac{2x}{2}=\frac{-\frac{17}{70}}{2}\) and simplifying: \(x=-\frac{17}{140}\)
