Part a) \((\frac{4}{7} )^{3}\)
\((\frac{4}{7} )^{3} =\frac{4^{3}}{7^{3}}= \frac{64}{343}\)
therefore
the answer part a) is equal to
\(\frac{64}{343}\)
Part b) \(\frac{6xyz}{2xz}\)
\(\frac{6xyz}{2xz}= \frac{(2xz)(3y)}{2xz} = 3y\)
therefore
the answer Part b) is equal to
\(3y\)
