\(x- \frac{4}{3} = 3x+ \frac{4}{7}\)
You want to put like terms on like sides.
\(x-3x = \frac{4}{3}+ \frac{4}{7}\)
Then on the right side use common denominator of 21:
\(-2x= \frac{28}{21}+ \frac{12}{21}\)
\(-2x = \frac{40}{21}\)
Then divide by -2 and get:
\(x = \frac{40}{21*-2} = \frac{-20}{21} = -.9524\)
