Answer:
\(2f - 1 +\frac{-10}{3f-4}\)
Step-by-step explanation:
Given :- \(\frac{6f^{2}-13-11f}{3f-4}\)
We perform this operation by long division method which is shown in figure-1
steps as follows:
1) we multiply 3f-4 by 2f and get 6f² -8 and then
2) subtract 6f² -8 from 6f² - 13 -11f ,we we get -3f - 13
3) now multiply 3f-4 by -1 and get -3f - 13
4) subtract -3f -3 from -3f -13 ,we we get -10
where dividend is 6f² - 13 -11f, divisor is 3f-4, Quotient is 2f - 1 and remainder is -10.
\(2f - 1 +\frac{-10}{3f-4}\)
