A race car starting from rest accelerates uniformly at 4.9 m/s^2. What is the car's speed after it has traveled 200 meters?
The equation v²=u²+2as will help with solving this equation
v is what we are trying to find
u=0
a=4.9
s=200
v²=0²+24.9200
v=√(24.9200)
v=√1960
v=44.3 m/s (3 sf)
Hello!
A race car starting from rest accelerates uniformly at a rate of 3.90 m/s² what is the cars speed after it has traveled 200 m.
We have the following data:
Vf (final velocity) = ? (in m/s)
Vi (initial velocity) = 0 m/s (accelerated from rest)
d (displacement) = 200 m
a (acceleration) = 4.90 m/s²
Since we do not need to know the time elapsed during the movement, we apply the data of the question to the Equation of Torricelli, let us see:
\(V_f^2 = V_i^2 + 2*a*d\)
\(V_f^2 = 0^2 + 2*4.90*200\)
\(V_f^2 = 0 + 1960\)
\(V_f^2 = 1960\)
\(V_f = \sqrt{1960}\)
\(V_f = 44.27188724...\)
\(\boxed{\boxed{V_f \approx 44.27\:m/s}}\:\:\:\:\:\:\bf\blue{\checkmark}\bf\green{\checkmark}\bf\red{\checkmark}\)
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