Verified Answer :

Willchemistry


Refine \(2(4z-3-1)\)

\(= 2(4z-4)\)

Refine : \(166 - 16 = 120\)

therefore:

\(2(z-4) = 120\)

Divide both sides by  2 :

\(\frac{2(z-4)}{2} = \frac{120}{2}\)

\(4z-4 = 60\)

add 4  to both sides:

\(4z-4+4 = 60+4\)

\(4z = 64\)

Divide both sides by 4 :

\(\frac{4z}{4} = \frac{64}{4}\)

\(z = 16\)

hope this helps!

Solutions 

1) Simplify 4z−3−1 to 4z−4

2(4z−4)=166−46

2) Simplify 166−46 to 120

2(4z−4)=120

3) Divide the equation from both sides by 2

4z−4=120 ÷ 2

4) Simplify 120 ÷ 2 to 60

4z−4=60

5)  Add 4 to both sides

4z=60+4

6) Simplify 60+4 to 64

4z=64

7) Divide both sides by 4z=64 ÷ 4

8) Simplify 64 ÷ 4 to 16

z=16


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