The events are independant (i.e. what she rolls on the cube has no impact on how the spinner works). The probability of two independant events is given by:
\(P_t = P_{cube} \times P_{spin}\)
For the cube, 1/2 the numbers meet our requitment of being even, so:
\(P_{cube} = \frac{Desired}{Total} = \frac{even}{total} = \frac{3}{6} =\frac{1}{2}\)
For the spinner, there are 3 odds out of 5 (1, 3 & 5) so:
\(P_{spin} =\frac{Desired}{Total} = \frac{odd}{total} = \frac{3}{5}\)
and then:
\(P_T = P_{cube} \times P_{spin}\)
\(P_T =\frac{1}{2} \times \frac{3}{5}\)
\(P_T =\frac{3}{10}\)
