First we should convert \(36 km h^{-1}\) to \(km s^{-1}\)
\(36 km h^{-1} = \frac{36}{(60)(60)} = .01 km s^{-1}\)
To find the distance travelled we use \(s = ut + \frac{1}{2} a t^{2}\)
Where:
s = distance travelled
\(u = .01 km s^{-1}\) (velocity)
t = 10 s (time)
\(a = 0 m s^{-2}\) (acceleration)
By inserting these values into the equation we get:
\(s = (.01)(10) + \frac{1}{2} (0) (10)^{2}\)
= (.01)(10)
= .1 km
