Evaluate (f-g)(3t) for f(x)=x²+1 and g(x)=x-4
\((f-g)(3t) \\ \\ f(x)-g(x) \\ \\ f(3t)-g(3t) \\ \\ ((3t)^2+1)-((3t)-4) \\ \\ 9t^2+1-3t+4 \\ \\ 9t^2-3t+5\)
f(x)=x²+1g(x)=x-4------------f(x)-g(x)=x²+1-(x-4)=x²+1-x+4=x²-x+5------------Therefore:(f-g)(3t)=(3t)²-3t+5=3²t²-3t+5=9t²-3t+5
