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mecca99
mecca99 mecca99
  • 18-04-2016
  • Chemistry
Answered

In order to prepare a 0.523 m aqueous solution of potassium iodide, how many grams of potassium iodide must be added to 2.00kg of water?

Verified Answer :

Willchemistry
Willchemistry Willchemistry
  • 18-04-2016

M = amount of the solute  / mass of the solvent

0.523 = x / 2.00 

x = 0.523 2.00

x = 1,046  moles

molar mass KI = 166.0028 g/mol

Mass = 1,046 166.0028

Mass ≈ 173.63 g

hope this helps!


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