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Jill jumped 6 1/3 feet in the long-jump event. Jill best friend jumped 6 5/7 feet. How much farther did Jill's best friend jumped? Describe in words the process you used to solve the problem.

Verified Answer :

calculista

Answer:

Jill's best friend jumped 8/21 feet further than Jill.

Step-by-step explanation:

we have that

Jill jumped 6 1/3 feet

Jill best friend jumped 6 5/7 feet

To find out how much farther did Jill's best friend jumped, subtract the length that Jill jumped from the length that Jill best friend jumped

\(6\frac{5}{7}-6\frac{1}{3}\)

but first convert mixed number to improper fraction

\(6\frac{5}{7}\ ft=\frac{6*7+5}{7}=\frac{47}{7}\ ft\)

\(6\frac{1}{3}\ ft=\frac{6*3+1}{3}=\frac{19}{3}\ ft\)

substitute the values

\(\frac{47}{7}-\frac{19}{3}=\frac{47*3-7*19}{21}=\frac{8}{21}\ ft\)

therefore

Jill's best friend jumped 8/21 feet further than Jill.

annedaniels226

Answer:

Kates best friend jumped 8/21 feet more than kate did

Step-by-step explanation:

First to find the difference between two fractions they need a common denominator, 21 works for this. Then the actual fractions need to match the denominator. 7/21 and 15/21 are our new frations. Then when subtraction you subtract the numerators, the answer to that is 8/21 after simplifying (in this case you cant) you subtract the whole numbers, 6 – 6 = 0 the add the whole and fraction together. Kates best friend jumped 8/21 more feet than kate did.

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