The answer is 5.2 × 10-2 newtons.
To calculate this, we will use Coulomb's Law:
F = \(\frac{k * Q_{1} * Q_{2} }{ r^{2} }\)
where F is repulcive force, k is constant, Q is charge, r is distance between charges.
If:
\(Q_{1}\) = \(Q_{2}\) = 1.2 × \(10^{-6}\) C²
r = 5.0 × \(10^{-1}\) C²
k = 5.0 × \(10^{9}\) \(\frac{N*m^{2} }{ C^{2} }\)
Then:
\(F = \frac{5.0* 10^{-1} \frac{N* m^{2} }{ C^{2}} * 1.2 * 10^{-6} C * 1.2 * 10^{-6} C }{(5.0* 10^{-1} m)^{2}}\)
⇒ \(F= \frac{9 * 1.2 * 1.2 * 10^{-3} N }{25* 10^{1} }\)
⇒\(F = \frac{12.96* 10^{-2} }{25} N\)
⇒ \(F = 5.2 N\)
