Factorise fully 2x^2-4xy
The answer isĀ 2x(x-2y)
x^2=xxundistribute propoertyab-ac=a(b-c)find a aka common factor2x^2=2xx4xy=22xycommon is 2*x=2xa=2x2x(x)-2x(2y)=2x(x-2y)