Answered

A jet engine develops 1.0 x 10 N of thrust to move an airplane forward

at a speed of 9.0 x 10 km/h. What

is the power output of the engine?

A jet engine develops 1.0 x 10 N of thrust to move an airplane forward at a speed of 9.0 x 10 km/h. What is the power output of the engine? class=

Verified Answer :

So P = 1.0x10^5N(900km/h1000m/km*1h/3600s) = 2.5x10&6W = 25 MW ans c

Answer:

Power, \(P=25\times 10^6\ W\)

Explanation:

Given that :

Force applied to the engine, \(F=1\times 10^5\ N\)

Speed of the engine, \(v=9\times 10^2\ km/h=250\ m/s\)

To find :

The power output of the engine

Solve :

Power output of the engine is given by :

\(P=\dfrac{W}{t}\)

W is the work done

t is the time taken

Also, \(W=F\times d\) and \(v=\dfrac{d}{t}\)

\(P=\dfrac{F\times d}{t}\)

\(P=F\times v\)

\(P=1\times 10^5\ N\times 250\ m/s\)

\(P=25\times 10^6\ W\)

So, the power output of the engine is \(25\times 10^6\ W\).