One point on the line is (1,3) and another point is (9,11).
Find the slope of the two points on the line.
\(\bf{Slope =\frac{y_2-y_1}{x_2-x_1} =\frac{11-3}{9-1} =\frac{8}{8} = 1\)
Now, let's make our equation in the form of y = mx + b, where m is the slope and b is the y-intercept.
We now have y = 1x + b
Plug in a point and solve for b.
y = 1x + b
3 = 1(1) + b
3 = 1 + b
b = 2
The equation is y = x + 2.
