Answered

If the velocity of an object changes from 65 m/s to 98 m/s during a time interval of 12 s, what is the acceleration of the object?

Verified Answer :

a=acceleration
vf=final velocity
v₀=original velocity
t=time period

a=(vf-v₀)/t
a=(98 m/s-65 m/s)/12s=33 m/s / 12 s=2.75 m/s²

Answer: the acceleration of the object is 2.75 m/s²

AL2006


     Size of acceleration = (change in speed) / (time for the change)

Change in speed = (end speed) - (start speed)

                             =     (98 m/s)    -    (65 m/s)  =  33 m/s .

Time for the change = 12 s

Size of acceleration =  (33 m/s) / (12 s)

                                   =    (33/12) (m/s²)

                                   =        2.75 m/s² .