A line contains the point (8, –5). If the slope of the line is 5/7, write the equation of the line using point-slope form.

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JeanaShupp JeanaShupp · Answer 1 · 2019-04-17T12:17:19-04:00

Answer: \((y+5)=\frac{5}{7}(x-8)\)

Step-by-step explanation:

The point slope form of a line having slope m and point (a,b) is given by :-

\((y-b)=m(x-a)\)

Given: A line contains the point = (8, –5)

The slope of the line =\(\frac{5}{7}\)

Now, the point slope form of a line having slope \(\frac{5}{7}\) and point (8,-5) is given by :-

\((y-(-5))=\frac{5}{7}(x-8)\\\\\Rightarrow\ (y+5)=\frac{5}{7}(x-8)\)

Hence, the equation of the line =\((y+5)=\frac{5}{7}(x-8)\)

ColinJacobus ColinJacobus · Answer 2 · 2019-05-29T11:51:14-04:00

Answer: The required equation of the line is \(y+5=\dfrac{5}{7}(x-8).\)

Step-by-step explanation: Given that a line contains the point (8, -5) and the slope of the line is {tex]\dfrac{5}{7}.[/tex]

We are to write the equation of the line using point-slope form.

We know that

the equation of a line with slope m and passing through the point (a, b) is given by

\(y-b=m(x-a).\)

For the given line, we have

\(m=\dfrac{5}{7},~~~(a,b)=(8,-5).\)

Therefore, the equation of the line will be

\(y-b=m(x-a)\\\\\Rightarrow y-(-5)=\dfrac{5}{7}(x-8)\\\\\Rightarrow y+5=\dfrac{5}{7}(x-8).\)

Thus, the required equation of the line is \(y+5=\dfrac{5}{7}(x-8).\)