A volleyball team had 6 boys and 5 girls on it. The team needed 2 equipment managers. The coach selected 1 player at random to be an equipment manager and then selected 1 of the remaining players at random to be the other equipment manager.




What is the probability that both equipment managers were girls? Express your answer in simplest form.

Verified Answer :

there is a 25%chance because there is four possible outcomes

Proability first equipment manager is a girl: \(\frac{5}{11}\)
Probability second equipment manager is a girl: \(\frac{4}{10}\)

Probability both events occured = \(\frac{5}{11}\) x \(\frac{4}{10}\)
= 
\(\frac{2}{11}\)