Verified Answer :

DeannaJ

1)split into two fractions 
\(\frac{50a^{2} }{20a ^{3} b ^{3} }\) - \(\frac{10ab }{20a ^{3} b ^{3} }\)

2) cancel what you can on both sides
\(\frac{5}{2ab ^{3} }\) - \(\frac{1}{2a ^{2}b ^{2} }\)

3) Make the denominators the same by cross multiplying and then put together as 1 fraction again
\(\frac{5a-b}{2a ^{2}b ^{2} }\)

apologiabiology

remembe
(ax)/(bx)=(a/b)(x/x)=(a/b)1
find ones aka common factors and use distributive

top
50a^2-10ab
common facotrs is 10a
undistribute (ab+ac=a(b+c))
10a(5a-b)

bottom
20a^3b^3
see if 10a is also a common factor and undistribute that to cancel and make ones
10a(2a^2b^2)

now we have
\(\frac{10a(5a-b)}{10a(2a^{2}b^{3}}\)=\(\frac{10a}{10a}\) \(\frac{5a-b}{2a^{2}b^{3}}\)

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