Answer : The molarity of solution is, 0.0145 mole/L
Solution : Given,
Mass of solute, Na= 0.50 g
Volume of solution = 1.5 L
Molar mass of Na= 23 g/mole
Molarity : It is defined as the number of moles of solute present in the one liter of solution.
Formula used :
\(Molarity=\frac{w_b}{M_b\times V}\)
where,
\(w_b\) = mass of solute, Na
V = volume of solution in liters
\(M_b\) = molar mass of solute, Na
Now put all the given values in the above formula, we get the molarity of a solution.
\(Molarity=\frac{0.50g}{23g/mole\times 1.5L}=0.0145mole/L\)
Therefore, the molarity of solution is, 0.0145 mole/L
