Answer: 8.25 moles of oxygen are produced.
Explanation: The reaction follows:
\(2Al_2O_3(s)\rightarrow 4Al(s)+3O_2(g)\)
By Stoichiometry,
As, 4 moles of Aluminium is produced by 2 moles of aluminium oxide
11 moles of aluminium will be produced by = \(\frac{2}{4}\times 11=5.5moles\)
Now, 2 moles of aluminium oxide produces 3 moles of oxygen, so
5.5 moles of Aluminium oxide will produce = \(\frac{3}{2}\times 5.5=8.25moles\)
Hence, 8.25 moles of oxygen will be produced.
