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Find the area of each figure. Round to the nearest tenth if

necessary.

(Example

(02 cm

12 cm

6 yd

4.5 cm

16 yd

8 yd

2 cm

show) 24 yd

5 cm

1 m.

15 c

15 m

My Homework Independent practice eHelp Go online for Step-by-Step Solutions Find the area of each figure. Round to the nearest tenth if necessary. (Example (02 class=

Verified Answer :

The correct answers are:
 #1) 64 sq cm; #2) 240 sq yd; #3) 85.12 sq cm; #4) 193.3125 sq m.

Explanation:
#1) This can be broken into two rectangles, one with dimensions of 12 by 4.5 and one with dimensions of 2 by 5. The area of each rectangle is found by multiplying the length and the width; this gives us 124.5=54 and 25=10. Together this gives us 54+10=64.

#2) This can be broken into a rectangle with length 24 and width 8, and a triangle with base (24-6-6)=12 and height (16-8)=8.
The area of a rectangle is found by multiplying length and width; this gives us 248=192.
The area of a triangle can be found by multiplying 1/2bh; this gives us 1/2128=48. Together we have 192+48=240.

#3) This can be broken into a triangle with base 8 and height 15, and a circle with diameter 8.
The area of a triangle is given by 1/2bh; this gives us 1/2815=60.
The area of a circle is 3.14r²; since we have the diameter, we take half of it to find the radius. d=8, so r=8/2=4. We only want half of the circle, so we have 1/23.144²=25.12. Together this gives us 60+25.12=85.12.

#4) This can be broken into a rectangle with length 15 and with 7, and half of a circle with diameter 15.
The area of a rectangle is found by multiplying the length and width, which gives us 157=105.
The area of a circle is found by 3.14r²; we have the diameter, so we take half of it first. 15/2 = 7.5. We only want half of the circle, so we use 1/23.147.5²=88.3125. Together, this gives us 105+88.3125=193.3125.  

Answer:

1. 64 cm²

2. 240 yard²

3. 85.13 cm²

4. 193.36 m²

Step-by-step explanation:

Ques 1: We are given two rectangle with dimensions,

Length = 12 cm, Width = 4.5 cm and Length = 5 cm, Width = 2 cm.

As, we know, Area of a rectangle = Length × Width

So, we have,

Area of 1st rectangle = 12 × 4.5 = 54 cm²

Area of 2nd rectangle = 5 × 2 = 10 cm²

Thus, the total area of the figure = 54 + 10 = 64 cm²

Ques 2: We are given a triangle and a rectangle with dimensions,

Triangle: Base = 24-12 = 12 yd and Height = 8 yd

As, Area of a triangle = \(\frac{1}{2} (Base \times Height)\)

i.e. Area of the triangle =  \(\frac{1}{2} (12\times 8)\)

i.e. Area of the triangle =  \(\frac{1}{2}\times 96\)

i.e. Area of the triangle = 48 yard²

Rectangle: Length = 24 yd, Width = 8 yd

As, we know, Area of a rectangle = Length × Width

i.e. Area of a rectangle = 24 × 8 = 192 yard²

So, the total area of the figure = 48 + 192 = 240 yard².

Ques 3: We are given a triangle and a semi-circle with dimensions,

Triangle: Base = 8 cm and Height = 15 cm

As, Area of a triangle = \(\frac{1}{2} (Base \times Height)\)

i.e. Area of the triangle =  \(\frac{1}{2} (8\times 15)\)

i.e. Area of the triangle =  \(\frac{1}{2}\times 120\)

i.e. Area of the triangle = 60 cm²

Semi-circle: Diameter = 8 cm implies Radius = 4 cm.

So, Area of the semi-circle = \(\frac{\pi r^{2}}{2}\)

i.e. Area of the semi-circle = \(\frac{\pi 4^{2}}{2}\)

i.e. Area of the semi-circle = \(\frac{16\pi}{2}\)

i.e. Area of the semi-circle = \(\frac{50.26}{2}\)

i.e. Area of the semi-circle = 25.13 cm²

Thus, the total area of the figure = 60 + 25.13 = 85.13 cm²

Ques 4: We are given a rectangle and a semi-circle of dimensions,

Rectangle: Length = 15 m, Width = 7 m.

As, we know, Area of a rectangle = Length × Width

i.e. Area of a rectangle = 15 × 7 = 105 m²

Semi-circle: Diameter = 15 m implies Radius = \(\frac{15}{2}\) = 7.5 m

So, Area of the semi-circle = \(\frac{\pi r^{2}}{2}\)

i.e. Area of the semi-circle = \(\frac{\pi (7.5)^{2}}{2}\)

i.e. Area of the semi-circle = \(\frac{176.72}{2}\)

i.e. Area of the semi-circle = 88.36 m²

Thus, the total area of the figure = 105 + 88.36 = 193.36 m²

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