Which calculation set-up would be correct to determine the volume of concentrated hydrochloric acid (12.0 M HCl) that is required to make 500.0 milliliters of a 6.0 M HCl?
M₁ V₁ = M₂ V₂
12.0 V₁ = 6.0 500.0
12.0 V₁ = 3000
V₁ = 3000 / 12.0
V₁ = 250 mL
hope this helps!
Answer : The volume of concentrated hydrochloric acid is, 0.25 liters
Explanation :
Using neutralization law,
\(M_1V_1=M_2V_2\)
where,
\(M_1\) = molarity of concentrated hydrochloric acid = 12 M = 12 mole/L
\(M_2\) = molarity of hydrochloric acid = 6 M = 6 mole/L
\(V_1\) = volume of concentrated hydrochloric acid = ?
\(V_2\) = volume of hydrochloric acid = 500 ml = 0.5 L
Now put all the given values in the above formula, we get the volume of concentrated hydrochloric acid.
\(12mole/L\times V_2=6mole/L\times 0.5L\)
\(V_2=0.25L\)
Therefore, the volume of concentrated hydrochloric acid is, 0.25 liters