Which calculation set-up would be correct to determine the volume of concentrated hydrochloric acid (12.0 M HCl) that is required to make 500.0 milliliters of a 6.0 M HCl?

Verified Answer :

M₁ V₁ = M₂ V₂

12.0 V₁ = 6.0 500.0

12.0 V₁ = 3000

V₁ = 3000 / 12.0

V₁ = 250 mL

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Answer : The volume of concentrated hydrochloric acid is, 0.25 liters

Explanation :

Using neutralization law,

\(M_1V_1=M_2V_2\)

where,

\(M_1\) = molarity of concentrated hydrochloric acid = 12 M = 12 mole/L

\(M_2\) = molarity of hydrochloric acid = 6 M = 6 mole/L

\(V_1\) = volume of concentrated hydrochloric acid = ?

\(V_2\) = volume of hydrochloric acid = 500 ml = 0.5 L

Now put all the given values in the above formula, we get the volume of concentrated hydrochloric acid.

\(12mole/L\times V_2=6mole/L\times 0.5L\)

\(V_2=0.25L\)

Therefore, the volume of concentrated hydrochloric acid is, 0.25 liters