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Harper has $15.00 to spend at the grocery store. She is going to buy bags of fruit that cost $4.75 each and one box of crackers that costs $3.50.


Write and solve an inequality that models this situation and could be used to determine the maximum number of bags of fruit, b, Harper can buy.

Verified Answer :

wmd1999

since harper has only %15 that is the most she can spend, therefore we would have 15> or = 4.75b+3.5c.  the best way to solve this would be to divide 15 by 4.75, then round down to the nearest whole number. if you do this, you get 3 bags of fruit.

Answer:

4.75x + 3.75y ≤ 15 inequality models the given situation.

Harper can buy at maximum 3  bags of fruits.

Step-by-step explanation:

 Given : Harper has $15.00 to spend at the grocery store. She is going to buy bags of fruit that cost $4.75 each and one box of crackers that costs $3.50.  

We have to write and solve an inequality that models this situation and could be used to determine the maximum number of bags of fruit that  Harper can buy.

Let Harper buys 'x'  bags of fruit

and 'y'  box of crackers

Given : cost of one bags of fruits is $ 4.75

so the cost of x bags of fruits is 4.75x

Given : cost of one box of cracker is $ 3.50

so the cost of y box of crackers is 3.75y

also, Harper has $15.00 to spend at the grocery store

So the maximum amount he can spend is $15

So inequality become,

4.75x + 3.75y ≤ 15

So the maximum number of bags of fruit Harper can buy.

is when he buys no box of cracker.

Put y = 0 in above inequality , we have,

4.75x + 3.75(0) ≤ 15

4.75x  ≤ 15

Divide both side by 4.75

We have , x = 3.158 ≈ 3

So , Harper can buy at maximum 3  bags of fruits.

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