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Julian jogs 2 kilometers east, 4 kilometers north, and then 7 kilometers west. How far is Julian from his starting position, to the nearest tenth of a kilometer?

Verified Answer :

Matheng

Answer:

6.4 kilometer

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Step-by-step explanation:

See the attached figure.

Let Julian starts from point O (0,0)

Julian jogs 2 kilometers east ⇒ arrived to point A (2,0)

4 kilometers north ⇒ arrived to point B (2,4)

and then 7 kilometers west ⇒ arrived to point C (-5,4)

How far is Julian from his starting position?

So, it is required to find the distance OC

From the graph OC = \(\sqrt{(-5)^2+(4)^2}=\sqrt{25+16}  =\sqrt{41} =6.403\)

So, the distance from his starting position ≈ 6.4 km (to the nearest tenth of a kilometer)

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Answer:

The correct answer is 6.4 kilometers for khan Academy

Step-by-step explanation:

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