If the the target is 200 meters away and the bullet travels at 200 m/s, it will reach the target in one second.
So we need to calculate the distance the bullet will descend in one second.
Acceleration downwards due to gravity is 9.81 m/s.
We can utilize the formula \(D=\frac{V_{i}+V_{f}}{2} *t\) in equations with constant acceleration, where D is equal to distance, Vi = initial velocity, Vf = final velocity and t = time.
\(D= \frac{0+9.81}{2}*1\)
\(D=4.905\)
The bullet will land 4.905 meters below the center of the target.
