Solve for e:(-7)=e/3+14? show your work
-7 = \(\frac{e}{3}\) + 14take 14 to the other side-7 -(14) = \(\frac{e}{3}\)-21 = \(\frac{e}{3}\)Multiply by 3 on either sides to isolate e and to find a value-21 × 3 = \(\frac{e}{3}\) × 33 and 3 cancels out-63 = e
