to subtract fractions, we need a common denominator.
\(\frac{3}{y-2}\) - \(\frac{1}{y+3}\)
the common denominator will be (y-2)(y+3)
\(\frac{3(y+3)-1(y-2)}{(y-2)(y+3)}\)
\(\frac{3y + 9 - y + 2}{(y-2)(y+3)}\)
\(\frac{2y + 11}{(y-2)(y+3)}\)
The answer above will be the simplified form.
