Lets first find the slope:
(y₂-y₁)=m(x₂-x₁)
(-9-(-3)) = m(-4-6)
-6 = m(-10)
Isolate m:
\(\frac{-6}{-10}\) = \(\frac{m(-10)}{-10}\)
-10 and -10 cancels out
\(\frac{-6}{-10}\) = m
\(\frac{3}{5}\) = m
Now we know the slope, which is \(\frac{3}{5}\)
The equations is
y = mx + c
Take any two coordinates from the given above
Im taking (6,-3)
Plug in those coordinates and the slope to the formula
-3 = \(\frac{3}{5}\)(6) + c
-3 = \(\frac{18}{5}\) + c
Isolate c
-3 - \(\frac{18}{5}\) = c
\(- \frac{33}{5}\) = c
which gives us:
-6.6 = c
Now plug in the slope and c in the equation:
y = \(\frac{3}{5}\)x+ (-6.6)
or
y = \(\frac{3}{5}\)x +(-\(\frac{33}{5}\))
