Each time we are dividing by 4.
Essentially, multiplying by 1/4.
Since we're multiplying, that makes this a geometric sequence!
So: Our first term is 64, and the common ratio is 1/4.
Let's plug that into the geometric sequence formula.
\(a_n=a_1(r)^{n-1}\)
Where a_n = the value of the nth term
a_1 = the first term, and r = the common ratio
\(a_n=64(\frac14)^{n-1}\)
Now that we have our equation, let's plug in 10 for n.
That way, we can solve to find \(a_{10}\), the value of the 10th term.
\(a_{10}=64(\frac14)^{10-1}=\boxed{\frac{1}{4096}}\)
