The answer is B) 8.
There are 5 genes. There are two possibilities for each of the heterozygous genes and only one possibility for each of homozygous genes. So, the possibilities for each gene are:
Aa - 2: A or a;
Bb - 2: B or b;
CC - 1: D;
Dd - 2: D or d;
EE - 1: E.
Genotype AaBbCCDdEE will have
2 x 2 x 1 x 2 x 1 gametes
Thus, there will be 8 unique gametes produced by an individual with the genotype AaBbCCDdEE
