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  • 07-04-2016
  • Mathematics
Answered

x squared + ysquared-6y=-5

Verified Answer :

Anonymous Anonymous
  • 07-04-2016

Standard Form of the circle:  

\(x^{2} +(y-3) ^{2} =14\)

For y:

y=3 (+/-) \(\sqrt{-x} ^{2} +14\)

For x:

x=\(\sqrt{-y ^{2} } +6y+5 and - \sqrt{-y} ^{2} +6y+5\)

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