the only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54
remember if we can do
xy=0 then assume x and y=0
so factor
0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is
if you have
ax^2+bx+c=0 then
x=\(\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}\)
x^2+7x+18
a=1
b=7
c=18
x=\(\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}\)
x=\(\frac{-7+/- \sqrt{49-72} }{2}\)
x=\(\frac{-7+/- \sqrt{-23} }{2}\)
i=√-1
x=\(\frac{-7+/- i\sqrt{23} }{2}\)
the zerose would be
x=\(\frac{-7+ i\sqrt{23} }{2}\) or \(\frac{-7- i\sqrt{23} }{2}\)
