Answer:
0.8% is a probability that a calculator chosen at random will be defective
Step-by-step explanation:
Probability of any event is given by:
\(P(A) = \frac{\text{Number of required outcomes}}{\text{Total number of possible outcomes}}\) where, A is any event.
As per the statement:
In a batch of 960 calculators, 8 were found to be defective.
here,
A = Defective calculator.
⇒Number of defective calculator = 8
and
Total number of outcomes = 960 calculators.
then by definition we have;
\(P(A) = \frac{8}{960}\)
Simplify:
\(P(A) \approx 0.00833333333\) = 0.833333333 %
Therefore, a probability that a calculator chosen at random will be defective to the nearest tenth place is, 0.8 %
