The numbers are \(x=1{\pm\sqrt{3}i }\\\) which multiplies to 4 and adds to 2.
Let x and y be two numbers which is multiplied to 4 and adds to 2.
So, x×y = 4...(1)
x + y=2...(2)
So, y=2-x
Put y=2-x in (1), we get
x×(2-x ) = 4
\(2x-x^{2} =4\\x^{2} -2x+4=0\\x=\frac{2\pm\sqrt{4-16} }{2} \\x=\frac{2\pm2\sqrt{3}i }{2}\\x=1{\pm\sqrt{3}i }\\\)
Therefore numbers are \(x=1{\pm\sqrt{3}i }\\\) which multiplies to 4 and adds to 2.
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