Verified Answer :

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\(\frac{b^{\frac{1}{2}}}{b^{\frac{1}{4}}}=b^{\frac{1}{2}-\frac{1}{4}}=b^{\frac{2}{4}-\frac{1}{4}}=b^{\frac{1}{4}}\)


\(\frac{4d^{\frac{5}{3}}}{3d}=\frac{4}{3} d^{\frac{5}{3}-1}= \frac{4}{3}d^{\frac{5}{3}-\frac{3}{3}}=\frac{4}{3}d^{\frac{2}{3}}\)

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