We use the quadratic formula
x = \(\frac{-b +or- \sqrt{b^{2}-4ac } }{2a}\)
3x² + 12x + 6 = 0
║ ║ ║
a=3 b=12 c=6
Plug it in:
\(\frac{-12 +or- \sqrt{12 ^{2} -4(3)(6)} }{2(3)}\)
\(\frac{-12+or- \sqrt{144-72} }{6}\)
\(\frac{-12+or- \sqrt{72} }{6}\)
Solutions:
sol.1=\(\frac{-12+ \sqrt{72} }{6}\)
= -0.585786
≈ -0.6
sol.2 =\(\frac{-12- \sqrt{72} }{6}\)
= -3.41421
≈ -3.4
