jackyboy4536
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The teacher asked 4 students to measure 4 different objects. The table shown represents their measurements. Which student had the largest percent error?

The teacher asked 4 students to measure 4 different objects. The table shown represents their measurements. Which student had the largest percent error? class=

Verified Answer :

the correct answer is student four because it was off the most  

TaeKwonDoIsDead

Answer:

Student #4


Step-by-step explanation:

The formula for percentage error is given below. We will use this formula for all the four students and figure out whose error is the most.

Percentage Error =  \(|\frac{MeasuredValue-ActualValue}{ActualValue}|*100\)


  • For student 1:

% Error =  \(|\frac{49-50}{50}|*100\\=|-0.02|*100\\=(0.02)(100)\\=2\)

  • For student 2:

% Error =  \(|\frac{25.5-25}{25}|*100\\=|0.02|*100\\=(0.02)(100)\\=2\)

  • For student 3:

% Error =  \(|\frac{7.5-8}{8}|*100\\=|-0.0625|*100\\=(0.0625)(100)\\=6.25\)

  • For student 4:

% Error =  \(|\frac{2.1-1.6}{1.6}|*100\\=|0.3125|*100\\=(0.3125)(100)\\=31.25\)


Clearly, 31.25% error of student #4 is the highest.

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