Verified Answer :

penfila11Pen

Thats simple!
h(x)= \(\frac{x^{2}+3x }{4x+27}\)
find h(-8)
All we need to do is PLUG IN THE -8
h(-8)= \(\frac{(-8)^{2}+3(-8) }{4(-8)+27}\)
        =\(\frac{64-24}{-32+27}\) (negative²=positive,                                                                                negative×positive=negative)
        =\(\frac{40}{-5}\)
h(-8)=-8

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