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Please do #1 on each. Please show your work. If you don't know DON'T ANSWER. If you need to ask me questions please use Ask for Details.

Please do 1 on each. Please show your work. If you don t know DON T ANSWER. If you need to ask me questions please use Ask for Details. class=
Please do 1 on each. Please show your work. If you don t know DON T ANSWER. If you need to ask me questions please use Ask for Details. class=

Verified Answer :

i only know the answer for the second question.
the answer is20
11-3=8
85=40
40-30=10
102=20
the first one is 48
1+2=3
34=12
12+3=15
15+1=16
163=48

Geniustwins2426

The answer of question #1 is 48.
To solve this, first you have to solve the (2+1) and that equals 3, now you solve 4(2+1), and that equals 12. Next, you solve the [4(2+1)+3] and that equals 15. Then, you solve {1+[4(2+1)+3} and that equals 16. Lastly, 3{1+[4(2+1)+3} equals 3 times 16=48.

3{1+[4(2+1)+3}=3[1+(4x3+3)]
=3(1+12+3)=3x16=48

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