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A stone thrown horizontally at a speed of 5m/s from the top of a cliff 78.4m high.

AHow long does it take the stone to reach the bottom of the cliff?
BHow far from the base of the cliff does the stone strike the ground?

Verified Answer :

At=?
h = v1(y direction) t +1/2 gtt
78.4=0 t + 1/29.8tt
78.4 = 0+ 4.9 tt
tt=t(squqre) =78.4/4.9 =16
so t = sqrt16 =4 sec. the time needed to hit the ground.
B) how far =x =?
x =v(horizontal) t =5*4 =20 m.

a) It will take 4 seconds to reach the bottom of the cliff

b) The stone strike at a distance of 20 m from the bottom of the cliff

What is equation of motion?

It is an equation that describe the behavior of a physical system in terms of its motion as a function of time

using equation of motion

since, it is thrown initial horizontally at a speed of = 5m/s

initial vertical velocity = 0

s = u t + 1/2g(t^2)

78.4 = 1/2 9.8 (t^2)

t^2 = (78.4 2)/9.8

t = (16)^(1/2)

t= 4sec

a) It will take 4 seconds to reach the bottom of the cliff

b) distance from the base of cliff stone strike = horizontal velocity time

                                                                               5 m/s * 4 second

                                                                                20 m

hence , the stone strike at a distance of 20 m from the bottom of the cliff

learn more about equation of  motion

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