Answer:
\(5\frac{5}{6}\approx 5.833\) acres of land would be needed for 7 houses.
\(\frac{25}{6}\approx 4.17\) acres of land was left unused.
Step-by-step explanation:
We have been given that each house will be built on 5/6 of an acre.
To find the area it will take to build 7 houses, we will multiply area need to build one house by 7 as:
\(\frac{5}{6}\times 7\)
\(\frac{35}{6}\)
\(5\frac{5}{6}\approx 5.833\)
Therefore, \(5\frac{5}{6}\approx 5.833\) acres of land would be needed for 7 houses.
Since builder began with 10 acres of land, so we can find the unused land by subtracting \(5\frac{5}{6}\) from 10 as:
\(10-5\frac{5}{6}\)
\(10-\frac{35}{6}\)
\(\frac{10*6}{6}-\frac{35}{6}\)
\(\frac{60}{6}-\frac{35}{6}\)
\(\frac{60-35}{6}\)
\(\frac{25}{6}\)
\(\frac{25}{6}\approx 4.17\)
Therefore, \(\frac{25}{6}\approx 4.17\) acres of land was left unused.
