At how many points does the graph of the function below intersects the x-axis?
y=3x^2-5x+1
c, 2
Unfortunately it doesn't factor nicely. You can try completing the square but it's really hard because A isn't 1. Because A is positive, you know that the parabola opens upwards. That means if you can find a negative function value then it definitely crosses the x axis twice because of symmetry. If you plug in 1 for x then y is -1. So the answer is C. 2.
Answer: 2 points
Step-by-step explanation: the graph of y=3x^2-5x+1 intersect the x-axis at those real values of x where y=0
i.e. 3x^2-5x+1=0
ax²+bx+c=0 has real roots if b²-4ac≥0
if b²-4ac=0 implies real and equal roots
here a=3,b=-5 and c=1
b²-4ac=25-12>0
this implies that this equation has unequal real roots
so,this equation will intersect the x-axis at two distinct points