Answered

If 3.85 moles of aluminum (Al) metal, with a density of 2.70 g/mL, are needed for a chemical reaction, how many milliliters of aluminum are needed?


Select one:

A1.43 mL Al
B18.9 mL Al
C38.5 mL Al
D281 mL Al

Verified Answer :

To find mL of Al needed, start by finding grams of Al that are being used in this reaction:
(3.85mol Al)(27.0g/mol Al)= 104g Al needed.

Since density is m/v, and we know the density and the mass, we can find the volume:
2.70g/mL = (104.g)/mL
Isolate mL:
(104.g)/(2.70g/mL) = 38.5mL needed which is answer C :)

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